Optimal. Leaf size=172 \[ -\frac{2 b (e+f x)^{5/2} (-2 a d f+b c f+b d e)}{5 d^2 f^2}+\frac{2 (e+f x)^{3/2} (b c-a d)^2}{3 d^3}+\frac{2 \sqrt{e+f x} (b c-a d)^2 (d e-c f)}{d^4}-\frac{2 (b c-a d)^2 (d e-c f)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{e+f x}}{\sqrt{d e-c f}}\right )}{d^{9/2}}+\frac{2 b^2 (e+f x)^{7/2}}{7 d f^2} \]
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Rubi [A] time = 0.156675, antiderivative size = 172, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {88, 50, 63, 208} \[ -\frac{2 b (e+f x)^{5/2} (-2 a d f+b c f+b d e)}{5 d^2 f^2}+\frac{2 (e+f x)^{3/2} (b c-a d)^2}{3 d^3}+\frac{2 \sqrt{e+f x} (b c-a d)^2 (d e-c f)}{d^4}-\frac{2 (b c-a d)^2 (d e-c f)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{e+f x}}{\sqrt{d e-c f}}\right )}{d^{9/2}}+\frac{2 b^2 (e+f x)^{7/2}}{7 d f^2} \]
Antiderivative was successfully verified.
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Rule 88
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(a+b x)^2 (e+f x)^{3/2}}{c+d x} \, dx &=\int \left (-\frac{b (b d e+b c f-2 a d f) (e+f x)^{3/2}}{d^2 f}+\frac{(-b c+a d)^2 (e+f x)^{3/2}}{d^2 (c+d x)}+\frac{b^2 (e+f x)^{5/2}}{d f}\right ) \, dx\\ &=-\frac{2 b (b d e+b c f-2 a d f) (e+f x)^{5/2}}{5 d^2 f^2}+\frac{2 b^2 (e+f x)^{7/2}}{7 d f^2}+\frac{(b c-a d)^2 \int \frac{(e+f x)^{3/2}}{c+d x} \, dx}{d^2}\\ &=\frac{2 (b c-a d)^2 (e+f x)^{3/2}}{3 d^3}-\frac{2 b (b d e+b c f-2 a d f) (e+f x)^{5/2}}{5 d^2 f^2}+\frac{2 b^2 (e+f x)^{7/2}}{7 d f^2}+\frac{\left ((b c-a d)^2 (d e-c f)\right ) \int \frac{\sqrt{e+f x}}{c+d x} \, dx}{d^3}\\ &=\frac{2 (b c-a d)^2 (d e-c f) \sqrt{e+f x}}{d^4}+\frac{2 (b c-a d)^2 (e+f x)^{3/2}}{3 d^3}-\frac{2 b (b d e+b c f-2 a d f) (e+f x)^{5/2}}{5 d^2 f^2}+\frac{2 b^2 (e+f x)^{7/2}}{7 d f^2}+\frac{\left ((b c-a d)^2 (d e-c f)^2\right ) \int \frac{1}{(c+d x) \sqrt{e+f x}} \, dx}{d^4}\\ &=\frac{2 (b c-a d)^2 (d e-c f) \sqrt{e+f x}}{d^4}+\frac{2 (b c-a d)^2 (e+f x)^{3/2}}{3 d^3}-\frac{2 b (b d e+b c f-2 a d f) (e+f x)^{5/2}}{5 d^2 f^2}+\frac{2 b^2 (e+f x)^{7/2}}{7 d f^2}+\frac{\left (2 (b c-a d)^2 (d e-c f)^2\right ) \operatorname{Subst}\left (\int \frac{1}{c-\frac{d e}{f}+\frac{d x^2}{f}} \, dx,x,\sqrt{e+f x}\right )}{d^4 f}\\ &=\frac{2 (b c-a d)^2 (d e-c f) \sqrt{e+f x}}{d^4}+\frac{2 (b c-a d)^2 (e+f x)^{3/2}}{3 d^3}-\frac{2 b (b d e+b c f-2 a d f) (e+f x)^{5/2}}{5 d^2 f^2}+\frac{2 b^2 (e+f x)^{7/2}}{7 d f^2}-\frac{2 (b c-a d)^2 (d e-c f)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{e+f x}}{\sqrt{d e-c f}}\right )}{d^{9/2}}\\ \end{align*}
Mathematica [A] time = 0.172243, size = 160, normalized size = 0.93 \[ \frac{2 \left (105 (b c-a d)^2 (d e-c f) \left (\frac{\sqrt{e+f x}}{d}-\frac{\sqrt{d e-c f} \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{e+f x}}{\sqrt{d e-c f}}\right )}{d^{3/2}}\right )-\frac{21 b d (e+f x)^{5/2} (-2 a d f+b c f+b d e)}{f^2}+35 (e+f x)^{3/2} (b c-a d)^2+\frac{15 b^2 d^2 (e+f x)^{7/2}}{f^2}\right )}{105 d^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.011, size = 644, normalized size = 3.7 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.35319, size = 1466, normalized size = 8.52 \begin{align*} \left [-\frac{105 \,{\left ({\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3}\right )} e f^{2} -{\left (b^{2} c^{3} - 2 \, a b c^{2} d + a^{2} c d^{2}\right )} f^{3}\right )} \sqrt{\frac{d e - c f}{d}} \log \left (\frac{d f x + 2 \, d e - c f + 2 \, \sqrt{f x + e} d \sqrt{\frac{d e - c f}{d}}}{d x + c}\right ) - 2 \,{\left (15 \, b^{2} d^{3} f^{3} x^{3} - 6 \, b^{2} d^{3} e^{3} - 21 \,{\left (b^{2} c d^{2} - 2 \, a b d^{3}\right )} e^{2} f + 140 \,{\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3}\right )} e f^{2} - 105 \,{\left (b^{2} c^{3} - 2 \, a b c^{2} d + a^{2} c d^{2}\right )} f^{3} + 3 \,{\left (8 \, b^{2} d^{3} e f^{2} - 7 \,{\left (b^{2} c d^{2} - 2 \, a b d^{3}\right )} f^{3}\right )} x^{2} +{\left (3 \, b^{2} d^{3} e^{2} f - 42 \,{\left (b^{2} c d^{2} - 2 \, a b d^{3}\right )} e f^{2} + 35 \,{\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3}\right )} f^{3}\right )} x\right )} \sqrt{f x + e}}{105 \, d^{4} f^{2}}, -\frac{2 \,{\left (105 \,{\left ({\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3}\right )} e f^{2} -{\left (b^{2} c^{3} - 2 \, a b c^{2} d + a^{2} c d^{2}\right )} f^{3}\right )} \sqrt{-\frac{d e - c f}{d}} \arctan \left (-\frac{\sqrt{f x + e} d \sqrt{-\frac{d e - c f}{d}}}{d e - c f}\right ) -{\left (15 \, b^{2} d^{3} f^{3} x^{3} - 6 \, b^{2} d^{3} e^{3} - 21 \,{\left (b^{2} c d^{2} - 2 \, a b d^{3}\right )} e^{2} f + 140 \,{\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3}\right )} e f^{2} - 105 \,{\left (b^{2} c^{3} - 2 \, a b c^{2} d + a^{2} c d^{2}\right )} f^{3} + 3 \,{\left (8 \, b^{2} d^{3} e f^{2} - 7 \,{\left (b^{2} c d^{2} - 2 \, a b d^{3}\right )} f^{3}\right )} x^{2} +{\left (3 \, b^{2} d^{3} e^{2} f - 42 \,{\left (b^{2} c d^{2} - 2 \, a b d^{3}\right )} e f^{2} + 35 \,{\left (b^{2} c^{2} d - 2 \, a b c d^{2} + a^{2} d^{3}\right )} f^{3}\right )} x\right )} \sqrt{f x + e}\right )}}{105 \, d^{4} f^{2}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 51.3928, size = 236, normalized size = 1.37 \begin{align*} \frac{2 b^{2} \left (e + f x\right )^{\frac{7}{2}}}{7 d f^{2}} + \frac{\left (e + f x\right )^{\frac{5}{2}} \left (4 a b d f - 2 b^{2} c f - 2 b^{2} d e\right )}{5 d^{2} f^{2}} + \frac{\left (e + f x\right )^{\frac{3}{2}} \left (2 a^{2} d^{2} - 4 a b c d + 2 b^{2} c^{2}\right )}{3 d^{3}} + \frac{\sqrt{e + f x} \left (- 2 a^{2} c d^{2} f + 2 a^{2} d^{3} e + 4 a b c^{2} d f - 4 a b c d^{2} e - 2 b^{2} c^{3} f + 2 b^{2} c^{2} d e\right )}{d^{4}} + \frac{2 \left (a d - b c\right )^{2} \left (c f - d e\right )^{2} \operatorname{atan}{\left (\frac{\sqrt{e + f x}}{\sqrt{\frac{c f - d e}{d}}} \right )}}{d^{5} \sqrt{\frac{c f - d e}{d}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.25269, size = 572, normalized size = 3.33 \begin{align*} \frac{2 \,{\left (b^{2} c^{4} f^{2} - 2 \, a b c^{3} d f^{2} + a^{2} c^{2} d^{2} f^{2} - 2 \, b^{2} c^{3} d f e + 4 \, a b c^{2} d^{2} f e - 2 \, a^{2} c d^{3} f e + b^{2} c^{2} d^{2} e^{2} - 2 \, a b c d^{3} e^{2} + a^{2} d^{4} e^{2}\right )} \arctan \left (\frac{\sqrt{f x + e} d}{\sqrt{c d f - d^{2} e}}\right )}{\sqrt{c d f - d^{2} e} d^{4}} + \frac{2 \,{\left (15 \,{\left (f x + e\right )}^{\frac{7}{2}} b^{2} d^{6} f^{12} - 21 \,{\left (f x + e\right )}^{\frac{5}{2}} b^{2} c d^{5} f^{13} + 42 \,{\left (f x + e\right )}^{\frac{5}{2}} a b d^{6} f^{13} + 35 \,{\left (f x + e\right )}^{\frac{3}{2}} b^{2} c^{2} d^{4} f^{14} - 70 \,{\left (f x + e\right )}^{\frac{3}{2}} a b c d^{5} f^{14} + 35 \,{\left (f x + e\right )}^{\frac{3}{2}} a^{2} d^{6} f^{14} - 105 \, \sqrt{f x + e} b^{2} c^{3} d^{3} f^{15} + 210 \, \sqrt{f x + e} a b c^{2} d^{4} f^{15} - 105 \, \sqrt{f x + e} a^{2} c d^{5} f^{15} - 21 \,{\left (f x + e\right )}^{\frac{5}{2}} b^{2} d^{6} f^{12} e + 105 \, \sqrt{f x + e} b^{2} c^{2} d^{4} f^{14} e - 210 \, \sqrt{f x + e} a b c d^{5} f^{14} e + 105 \, \sqrt{f x + e} a^{2} d^{6} f^{14} e\right )}}{105 \, d^{7} f^{14}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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